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Use the normal distribution of fish lengths for which the mean is 9 inches and the standard deviation is 2 inches. Assume the variable x is normally distributed. (A) What percent of the fish are longer than 14 ​inches? (B) If 300 fish are randomly​ selected, about how many would you expect to be shorter than 8 ​inches?

Respuesta :

Answer:

Step-by-step explanation:

Given that fish length X is having the normal distribution  for which the mean is 9 inches and the standard deviation is 2 inches.

X : N(9,2)

A) [tex]P(X<14) = P(z<\frac{14-9}{2} )\\=P(Z<2.5)\\=0.5+0.4938\\=0.9938[/tex]

B) Here sample size = 300

[tex]P(X<8) = P(Z<\frac{8-9}{2} )=P(Z<-0.5)\\=0.3085[/tex]

Out of 300 fish we can expect 300(0.3085) to be shorter

i.e. 92.55=93 fish

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