Respuesta :
Explanation:
It is given that,
Initial velocity of the baseball, u = 0
Final velocity of the baseball, v = 97 mi/h = 43.36 m/s
Mass of baseball, m = 0.15 kg
Distance, s = 1.3 m
(a) Let a be the acceleration of the baseball. Use third equation of motion as :
[tex]v^2-u^2=2as[/tex]
[tex]a=\dfrac{v^2}{2s}[/tex]
[tex]a=\dfrac{43.36^2}{2\times 1.3}[/tex]
[tex]a=723.11\ m/s^2[/tex]
Force is given by :
F = m a
[tex]F=0.15\times 723.11=108.46\ N[/tex]
So, 108.46 N force is exerted on the ball.
(b) The pitcher would need to increase the force so as to alter the required force to reach the same speed if the mass of the ball is decreased.
Answer:
(a) 108.47 N
(b) increased
Explanation:
u = 0
v = 97 mi/h = 43.36 m/s
s = 1.30 m
m = 0.150 kg
(a) let a be the acceleration
Us third equation of motion
v^2 = u^2 + 2 a s
43.36 x 43.36 = 0 + 2 x a x 1.30
a = 723.11 m/s^2
Force = mass x acceleration = 0.150 x 723.11 = 108.47 N
Thus, the force exerted on the ball is 108.47 N.
(b) as the mass is decreased and speed be same so force should be increased.
