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A current of 9 A flows through an electric device with a resistance of 43 Q. What must be the applied voltage in this particular
uit?
A. 4.8 V
B. 387 V
C.4.8 A
D.387 A​

Respuesta :

MathPhys

Answer:

B. 387 V

Explanation:

Ohm's law states that the voltage is the product of the current and resistance.

V = IR

V = (9 A) (43 Ω)

V = 387 V

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