Answer:
0.8516 kg
Explanation:
K = 7.3 N/m
A = 12.7 cm
y = A/2, v = 32.2 cm/s
Use the formula for the speed of mass
[tex]v=\omega \sqrt{A^{2}-y^{2}}[/tex]
[tex]32.2=\omega \sqrt{A^{2}-\frac{A^{2}}{4}}}[/tex]
[tex]32.2=\omega \times \frac{\sqrt{3}}{2}\times 12.7[/tex]
ω = 2.93 rad/s
Now, [tex]\omega =^{\sqrt{\frac{K}{m}}}[/tex]
Where, m is the mass of block.
[tex]m=\frac{K}{\omega ^{2}}[/tex]
m = 7.3 / (2.93 x 2.93) = 0.8516 kg
