Respuesta :

Answer:

√3

Step-by-step explanation:

Given:

[tex]2\sqrt{27}+\sqrt{12}-3\sqrt{3}-2\sqrt{12}\\=2\sqrt{27}-\sqrt{12}-3\sqrt{3}\\[/tex]

Writing √12 =2√3 and 2√27=6√3

Now[tex]=6\sqrt{3}-2\sqrt{3}-3\sqrt{3}\\=\sqrt{3}[/tex] !