At 90°C the vapour pressure of l,2·dimethylbenzene is 20kPa and that of 1,3-dimethylbenzene is 18 kPa.w'hat is the composition of the vapour of an equimolar mixture of the two components?

Respuesta :

Answer:

19kPa

Explanation:

the total pressure is given by [tex]p_A+p_B[/tex]

The pressure [tex]p_A=X_A\times P^0_A[/tex]

similarly [tex]p_B=X_B\times P^0_B[/tex]

for equilibrium process let us consider both have one mole

so [tex]x_A=\frac{1}{1+1}=0.5[/tex]

similarly [tex]x_B=\frac{1}{1+1}=0.5[/tex]

so [tex]P_A=0.5\times 20=10kPa[/tex]

[tex]P_B=0.5\times 18=9kPa[/tex]

so total pressure=10+9=19 kPa