Respuesta :
Answer : The volume of stock solution will be, 215 ml
Solution :
According to the neutralization law,
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of HCl solution = 0.75 M
[tex]V_1[/tex] = volume of HCl solution = 575 ml
[tex]M_2[/tex] = molarity of stock solution = 2.0 M
[tex]V_2[/tex] = volume of stock solution = ?
Now put all the given values in the above law, we get the volume of stock solution.
[tex](0.75M)\times (575ml)=(2.0M)\times V_2[/tex]
[tex]V_2=215ml[/tex]
Therefore, the volume of stock solution will be, 215 ml
