Answer:
A = π(8 in)^2 = 64π in^2
Step-by-step explanation:
First determine the radius of the circular cross section.
The equation of the sphere is x^2 + y^2 = r^2, and here y = 6 and r = 10.
Find the value of x^2 (the square of the radius of the cross section):
x^2 + 6^2 = 10^2, or x^2 = 64. Then the radius of the circular cross section is √64 = 8.
The area of this circular cross section is thus A = π(8 in)^2 = 64π in^2
The required area of the cross section is 200.96 square inches.
A sphere of radius 10 inches. A perpendicular plan cut the sphere 6 inches apart the center. Area of the circular cross section to be determine.
Area of circle is given by the π times square of radius.
Here, radius of the cross section
R = [tex]\sqrt{10^2-6^2}[/tex]
R = √64
R = 8
Area of circle = πr^2
=3.14 * 8 * 8
= 200.96 square inches.
Thus, the required area of the cross section is 200.96 square inches.
Learn more about circle here:
brainly.com/question/11833983
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