contestada

One CD player is said to have a signal-to-noise ratio of 82 dB, whereas for a second CD player it is 98 dB. What is the ratio of intensities of the signal and the background noise for each device?

Respuesta :

Answer:

1st CD PLAYER- [tex]\frac{v_2}{v_1} = 10^{4.1}[/tex]

2nd CD PLAYER- [tex]\frac{v_2}{v_1} = 10^{4.9}[/tex]

Explanation:

for voltage ratio

[tex]log\frac{v_2}{v_1} =\frac{dB}{20}[/tex]

For 1st cd player

[tex]log\frac{v_2}{v_1} =\frac{82}{20}[/tex]

[tex]\frac{v_2}{v_1} = 10^{4.1}[/tex]

[tex]\frac{v_2}{v_1}  = 12589.25[/tex]

FOR 2ND PLAYER

[tex]log\frac{v_2}{v_1} =\frac{98}{20}[/tex]

[tex]\frac{v_2}{v_1} = 10^{4.9}[/tex]

[tex]\frac{v_2}{v_1} = 79432.852[/tex]