Answer:
[tex]\frac{1}{\sqrt{26}}[/tex].
Step-by-step explanation:
The minimun distance between a point and a plane is the perpendicular distance. The formula is
d = [tex]\frac{|Ax_0+By_0+Cz_0+D|}{\sqrt{A^{2}+B^{2}+C^{2}}}[/tex]
where [tex](x_0,y_0,z_0)=(2,0,1)[/tex], A=4, B=3, C=1 and D=-10. So, the distance is
d = [tex]\frac{|8+1-10|}{\sqrt{16+9+1}}[/tex]
d = [tex]\frac{|-1|}{\sqrt{26}}[/tex]
d = [tex]\frac{1}{\sqrt{26}}[/tex].
