x²/3 - x/2 - 1 = 0
Multiply both sides by 6:
2x² - 3x - 6 = 0
It doesn't seem like you can use algebra to find the zeros, so we'll use the quadratic formula to find them:
x = -b±[tex]\frac{\sqrt{b^{2}-4ac}}{2a}[/tex]
a = 2, b = -3, c = -6
x = 2.637, -1.137
