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#14-8: A sack contains only purple, green, and yellow beads. If selected at random, the P(purple)= 1/5 and P(green)= 1/10. What is the probability of selecting a yellow bead? Express the probability as a number between 0 and 1.

Respuesta :

jcherry99

Answer:

0.7

Step-by-step explanation:

The way to solve this is to subtract the two fractions from 1.

P(y) = 1 - (1/5 + 1/10)

P(y) = 1 - (2/10 + 1/10)

P(y) = 1 - (3/10)

P(y) = 7/10

7/10 = 0.7

Answer:

P(yellow) = [tex]\frac{7}{10}[/tex]

Step-by-step explanation:

A sack contains: Purple, Green and Yellow beads

If selected at random;

P(purple) = [tex]\frac{1}{5}[/tex]

P(green) =  [tex]\frac{1}{10}[/tex]

P(yellow) = x

P(purple) + P(green) + P(yellow) = 1

i.e  [tex]\frac{1}{5}[/tex] +  [tex]\frac{1}{10}[/tex] + x = 1

x = 1 - ( [tex]\frac{1}{5}[/tex] +  [tex]\frac{1}{10}[/tex]) =  [tex]\frac{7}{10}[/tex]

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