Answer:
D
Step-by-step explanation:
Factorise the numerator and denominator
2x² - 5x + 3 = (x - 1)(2x - 3)
4x² - 12x + 9 = (2x - 3)²
Hence
[tex]\frac{f(x)}{g(x)}[/tex]
= [tex]\frac{2x^2-5x+3}{4x^2-12x+9}[/tex]
= [tex]\frac{(x-1)(2x-3)}{(2x-3)^2}[/tex]
Cancel the factor (2x - 3) on the numerator/denominator leaving
[tex]\frac{x-1}{2x-3}[/tex] → D
