Wavelength The crystal field splitting in Cr(CN)6]3-is Д,-5.51 x 10-19 J. At what wavelength will the [Cr(CN on absorb light most strongly (in nm)? constants: Planck's constant h = 6.626 × 10-34 J·s, speed of light c = 2.998 × 108 m/s

Respuesta :

Answer : The wavelength will be, 360.5 nm

Explanation :

Formula used :

[tex]\Delta_o=\frac{h\times c}{\lambda}[/tex]

where,

[tex]\Delta_o[/tex] = crystal field splitting energy = [tex]5.51\times 10^{-19}J[/tex]

h = Planck's constant = [tex]6.626\times 10^{-34}Js[/tex]

c = speed of light = [tex]2.998\times 10^8m/s[/tex]

[tex]\lambda[/tex] = wavelength = ?

Now put all the given values in the above formula, we get:

[tex]5.51\times 10^{-19}J=\frac{(6.626\times 10^{-34}Js)\times (2.998\times 10^8m/s)}{\lambda}[/tex]

[tex]\lambda=3.605\times 10^{-7}m=360.5\times 10^{-9}m=360.5nm[/tex]

conversion used : [tex](1nm=10^{-9}m)[/tex]

Therefore, the wavelength will be, 360.5 nm