Answer:
129 g of ice would be melted by the energy obtained as 16.1 [tex]^{0}\textrm{C}[/tex]
Explanation:
Total amount of heat obtained as 16.1 g of steam is condensed at 100 [tex]^{0}\textrm{C}[/tex] and cooled to 0 [tex]^{0}\textrm{C}[/tex] = [heat released during condensation of steam]+[heat released during cooling of steam to 0 [tex]^{0}\textrm{C}[/tex]]
So, Total amount of heat obtained as 16.1 g of steam is condensed at 100 [tex]^{0}\textrm{C}[/tex] and cooled to 0 [tex]^{0}\textrm{C}[/tex] = [[tex][16.1\times 2258]J+[16.1\times 4.18\times (100-0)]J[/tex] = 43083.6 J
To melt 1 g of ice, 333 J of heat is required. Therefore 43083.6 J of heat would melt (43083.6/333) g of ice or 129 g of ice.
