contestada

A steam heat engine is used to supply 14600 hp of power to a nearby city. The heat engine has a thermal efficiency of 33%. What is the rate of heat rejection by this heat engine?

Respuesta :

Answer:

34066.6 hp

Explanation:

We have given efficiency=33%=0.33

[tex]efficiency=\frac{W}{Q_1}[/tex]

[tex]Q_1=\frac{W}{efficiency}[/tex]

[tex]Q_1=\frac{14600}{0.33}=44242.4242\ hp[/tex]

we know that [tex]W=Q_1-Q_2[/tex]

[tex]Q_2=Q_1-W[/tex]

=44242.4242-14600=29642.4242HP

so the value of [tex]Q_2[/tex] the rate of heat of rejection is 29642.4242 hp

Ver imagen aristeus

Otras preguntas