Respuesta :
Answer:
Part a)
[tex]L = 18 kg m^2/s[/tex]
Part b)
[tex]v = 0.6 m/s[/tex]
Part c)
[tex]R_{max} = 6.04 kg[/tex]
[tex]R_{min} = 5.96 kg[/tex]
Explanation:
As we know that Ferris wheel start from rest with angular acceleration
[tex]\alpha = 0.001 rad/s^2[/tex]
time taken = 2 min
so here we have its angular speed after t = 2min given as
[tex]\omega = \alpha t[/tex]
[tex]\omega = (0.001)(2\times 60)[/tex]
[tex]\omega = 0.12 rad/s[/tex]
Part a)
Angular momentum of the Penguine about the center of the wheel is given as
[tex]L = I\omega[/tex]
[tex]L = (6\times 5^2)(0.12)[/tex]
[tex]L = 18 kg m^2/s[/tex]
Part b)
tangential speed is given as
[tex]v = r\omega[/tex]
[tex]v = (5)(0.12)[/tex]
[tex]v = 0.6 m/s[/tex]
Part c)
Maximum reading of the scale at the lowest point is given as
[tex]R_{max} = \frac{m\omega^2 r + mg}{g}[/tex]
[tex]R_{max} = \frac{6(0.12^2)(5) + 6(9.81)}{9.81}[/tex]
[tex]R_{max} = 6.04 kg[/tex]
Minimum reading of the scale at the top point is given as
[tex]R_{min} = \frac{mg - m\omega^2 r}{g}[/tex]
[tex]R_{min} = \frac{6(9.81) - 6(0.12^2)(5)}{9.81}[/tex]
[tex]R_{min} = 5.96 kg[/tex]
