Answer with explanation:
Sample mean of 81 full Professor = $ 77,220
Sample Standard Deviation (S)= $ 4500
Sample mean= $77,220
[tex]Z_{98 \text{Percent}=\frac{98}{100}}\\\\Z_{98 \text{Percent}=0.8365}\\\\Z_{\text Score=\frac{\bar x -\mu}{\sigma}}\\\\0.84=\frac{77220- \mu}{4500}\\\\\mu=77220-3780\\\\ \mu=73440[/tex]
So, When , z=98% , then Mean Salary ( μ)=73,440