An electrical device draws 4.68 A at 220 V. (a) If the voltage drops by 31%, what will be the current, assuming the resistance doesn't change?

Respuesta :

Answer:

The current will be 3.23 A.

Explanation:

Given that,

Current I = 4.68 A

Voltage V = 220 volt

We need to calculate the resistance

Using ohm's law

[tex]V = I R[/tex]

[tex]R = \dfrac{V}{I}[/tex]

Where,

V = voltage

I = current

R = resistance

Put the value into the formula

[tex]R = \dfrac{220}{4.68}[/tex]

[tex]R = 47\ \Omega[/tex]

We need to calculate the current

If the voltage drops by 31%

Voltage will be

[tex]V'=V-V\times31%[/tex]

[tex]V'=220-220\times\dfrac{31}{100}[/tex]

[tex]V'=151.8\ volt[/tex]

Now, the current will be

[tex]I = \dfrac{151.8}{47}[/tex]

[tex]I=3.23\ A[/tex]

Hence, The current will be 3.23 A.