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Having freckles (F) is dominant over not having freckles (f). A parent with freckles is crossed with a parent without freckles. The Punnett square shows the possible genotypes of the offspring.

What is the probability that an offspring will have a homozygous dominant genotype?
%

What is the probability that an offspring will have a heterozygous genotype?
%

What is the probability that an offspring will have a homozygous recessive genotype?
%

Respuesta :

ChrisxD5

Answer:

A: Freckles (Ff) B:No freckles (ff) C: Freckles (Ff) D:No freckles (ff)

A Monohybrid cross is a cross among two individuals with different variations of a trait located on the same locus of importance.

The dominant allele is: Having freckles: F

The recessive allele is: Not having freckles: f

  • For a cross between Heterozygous dominant parent (Ff) and purebred recessive parent (ff) refer to the image given below:

1.The probability of an offspring being a purebred dominant genotype: 0%

2.The probability of an offspring being heterozygous: 50%

3.The probability of offspring to be purebred recessive: 50%

  • In another case where the dominant parent is purebred (FF) and the other parent is purebred recessive (ff) then:  

1.The probability for offspring to be purebred dominant: 0%

2.The probability of an offspring to be heterozygous: 100%  

3.The probability of offspring to be purebred recessive: 0%

Therefore, the Punnett square is used to show the cross between the heterozygous dominant and purebred recessive parent.

To learn further about monohybrid cross click the given link below:

https://brainly.com/question/24076691

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