Answer:
Capacitance of the second capacitor = 2C
Explanation:
[tex]\texttt{Capacitance, C}=\frac{\varepsilon_0A}{d}[/tex]
Where A is the area, d is the gap between plates and ε₀ is the dielectric constant.
Let C₁ be the capacitance of first capacitor with area A₁ and gap between plates d₁.
We have
[tex]\texttt{Capacitance, C}_1=\frac{\varepsilon_0A_1}{d_1}=C[/tex]
Similarly for capacitor 2
[tex]\texttt{Capacitance, C}_2=\frac{\varepsilon_0A_2}{d_2}=\frac{\varepsilon_0A_1}{\frac{d_1}{2}}=2\times \frac{\varepsilon_0A_1}{d_1}=2C[/tex]
Capacitance of the second capacitor = 2C
