Respuesta :
The length of the rope swing for the considered case is found being of 5 meters approximately.
How to find the period of oscillation of a simple gravity pendulum?
If we've got:
- Gravity constant = g
- Length of pendulum = L
Then, we get:
[tex]T \approx 2\pi \sqrt{\dfrac{L}{g}}[/tex]
This is the period of oscillation, the time taken for a complete cycle in a simple gravity pendulum.
Using the above formula, as for this case, we're specified that:
- Gravity constant = 9.8 m/s² = g
- Time taken for complete swing (back to forth and then again back) = 4.5 seconds. = T
Then, the length of the rope is obtained as:
[tex]T \approx 2\pi \sqrt{\dfrac{L}{g}} \: \rm \:sec\\\\L = \dfrac{T^2g}{4\pi^2} \: \rm meters\\\\\L \approx \dfrac{(4.5)^2\times 2\times (9.8)}{4\pi^2} \approx 5 \: \rm meters[/tex]
Thus, the length of the rope swing for the considered case is found being of 5 meters approximately
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