Answer:
Option B is the correct answer.
Explanation:
Refer the figure we have centripetal force at bottom of circle
[tex]F_c=F_t-F_w\\\\\frac{mv^2}{r}=F_t-mg\\\\F_t=m\left ( \frac{v^2}{r}+g\right )[/tex]
We have mass, m = 2 kg
Radius, r = 1.2 m
For circular motion to occur we have tension at top = 0
That is
[tex]\frac{mv^2}{r}=mg\\\\v=\sqrt{rg}[/tex]
Now let us find tension at bottom point
[tex]F_t=2\times \left ( \frac{rg}{r}+g\right )=4g=40N[/tex]
Option B is the correct answer.
