A spring with spring constant 20 N/m has a mass of 5.0 kg attached. The spring is compressed and released. What is the period of oscillation?

Respuesta :

Answer:

The period of oscillation is 3.14 sec.

Explanation:

Given that,

Spring constant = 20 N/m

Mass = 5.0 kg

We need to calculate the time period

Using formula of time period

[tex]T =2\pi\sqrt{\dfrac{m}{k}}[/tex]

m= mass

k = spring constant

[tex]T =2\times3.14\sqrt{\dfrac{5.0}{20}}[/tex]

[tex]T =3.14\ sec[/tex]

Hence, The period of oscillation is 3.14 sec.