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Select the correct answer
What are the real zeros of the function g(x) = x^3 + 2x^2 - x - 2?
A. 1,-1,2
B. 1,-1, -2 c. 1,-1
D. 2, -2, 1

Respuesta :

Answer:

B. 1.-1,-2

Step-by-step explanation:

[tex]g(x) = x ^{3} + 2 {x}^{2} - x - 2[/tex]

Substitute g(x)=0

[tex]0 = {x}^{3} + 2 {x}^{2} - x - 2[/tex]

Move the expression to the left

[tex]0 - {x}^{3} - 2 {x}^{2} + x + 2 = 0[/tex]

Factor out -x^2 from the expression

[tex] - {x}^{2} \times (x + 2) + x + 2 = 0[/tex]

Factor out (x+2) from the expression

[tex](x + 2) \times ({x}^{2} + 1) = 0[/tex]

When the product of the factor equals 0, at least one factor is 0

[tex]x + 2 = 0[/tex]

[tex] - {x}^{2}+ 1 > = 0[/tex]

Solve for x

[tex]x = - 2 \\ x = - 1\\ x = 1[/tex]

Answer:

B. 1.-1,-2

Step-by-step explanation:

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