Respuesta :
Answer:
Probability of the sticks weight being 2.44 oz or greater is 0.01017 .
Step-by-step explanation:
We are given that the manufacturer's website states that the average weight of each stick is 2.00 oz with a standard deviation of 0.19 oz.
Also, it is given that the weight of the drumsticks is normally distributed.
Let X = weight of the drumsticks, so X ~ N([tex]\mu = 2,\sigma^{2} = 0.19^{2}[/tex])
The standard normal z distribution is given by;
Z = [tex]\frac{X-\mu}{\sigma}[/tex] ~ N(0,1)
Now, probability of the sticks weight being 2.44 oz or greater = P(X >= 2.44)
P(X >= 2.44) = P( [tex]\frac{X-\mu}{\sigma}[/tex] >= [tex]\frac{2.44-2}{0.19}[/tex] ) = P(Z >= 2.32) = 1 - P(Z < 2.32)
= 1 - 0.98983 = 0.01017
Therefore, the probability of the sticks weight being 2.44 oz or greater is 0.01017 .
