For this case we must find the solution of the following quadratic equation:
[tex]50-x ^ 2 = 0[/tex]
Subtracting 50 from both sides of the equation:
[tex]-x ^ 2 = -50[/tex]
Multiplying by -1 on both sides of the equation:
[tex]x ^ 2 = 50[/tex]
We apply square root on both sides to eliminate the exponent:
[tex]x = \sqrt {50}\\x = \pm \sqrt {25 * 2}\\x = \pm \sqrt {5 ^ 2 * 2}\\x = \pm5 \sqrt {2}[/tex]
ANswer:
[tex]x = \pm5 \sqrt {2}[/tex]
