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Four points from a line are shown in the table below.
INPUT OUTPUT
10 -8
2 -6
4 -4 |
6 -2
Use the table to determine the slope-intercept form of the equation of the line.
A.
y = x - 8
B.
y = x + 8
C.
y = -8x + 1
D.
y = -8x - 1
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Four points from a line are shown in the table below INPUT OUTPUT 10 8 2 6 4 4 6 2 Use the table to determine the slopeintercept form of the equation of the lin class=

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Answer:

Correct choice is A. [tex]y=x-8[/tex].

Step-by-step explanation:

pick any two points from the table say (0,-8) and (2,-6)

Now we we can use both points to find the equation of line.

slope [tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{-6--8}{2-0}=\frac{2}{2}=1[/tex]

now plug slope m=1 and any point say (0,-8) into point slope formula

[tex]y-y_1=m\left(x-x_1\right)[/tex]

[tex]y--8=1\left(x-0\right)[/tex]

[tex]y+8=1\left(x\right)[/tex]

[tex]y+8=x[/tex]

[tex]y=x-8[/tex]

Hence correct choice is A. [tex]y=x-8[/tex].

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