Answer:
[tex]x_1=-4\\\\x_2=\frac{1}{3}[/tex]
Step-by-step explanation:
Given the quadratic equation:
[tex]2x^2+14x-4=-x^2+3x[/tex]
You can follow these steps in order to solve it:
- Make the equation equal to 0:
[tex]2x^2+14x-4+x^2-3x=0[/tex]
- Now, add the like terms:
[tex]3x^2+11x-4=0[/tex]
- Finally, apply the Quadratic formula ([tex]x=\frac{-b\±\sqrt{b^2-4ac} }{2a}[/tex]):
In this case we know that:
[tex]a=3\\b=11\\c=-4[/tex]
Therefore, substituting values into the Quadratic formula and evaluating, we get:
[tex]x=\frac{-11\±\sqrt{11^2-4(3)(-4)} }{2(3)}\\\\x_1=-4\\\\x_2=\frac{1}{3}[/tex]
