given,
[tex] \frac{ {y}^{3} - {y}^{2} + y + 3}{y + 1} \\ = \frac{ {y}^{3} + {y}^{2} - 2 {y}^{2} - 2y + 3y + 3}{x + 1} \\ = \frac{{y}^{2} (y + 1) - 2y(y + 1) + 3(y + 1)}{(y + 1)} \\ = \frac{(y + 1)( {y}^{2} - 2y + 3) }{(y + 1)} \\ = {y}^{2} - 2y + 3[/tex]