A quantity of CO gas occupies a volume of 0.32 L at 0.90 atm and 323 K . The pressure of the gas is lowered and its temperature is raised until its volume is 3.8 L . Find the density of the CO under the new conditions. Express your answer to two significant figures and include the appropriate units.
Mathematical formula of Ideal Gas Law is PV=nRT where: P-pressure, V-volume n-number of moles; m/MW T-Temperature m-mass d-density ; m/V MW-Molecular Weight R- Ideal Gas constant. If the units of P,V,n & T are atm, L, mol & K respectively, the value of R is 0.0821 L x atm / K x mol
Substituting the definitions to the original Gas equation becomes: d= P x MW / (RxT)
Solution : d= .90atm x 28 g/mol (CO) / 0.0821Lxatm / mol x K x 323 K
d = 25.2 g / 26000 mL
d = .0.00096 g/mL is the density of CO under the new conditions