Answer:
The area of the Mosaic increased [tex]3.25\ m^{2}[/tex]
Step-by-step explanation:
step 1
Find the area of the original Mosaic
The area of the square is equal to
[tex]A=b^{2}[/tex]
we have
[tex]b=3\ m[/tex]
substitute
[tex]A=(3)^{2}=9\ m^{2}[/tex]
step 2
Find the area of the increased Mosaic
The area of the square is equal to
[tex]A=b^{2}[/tex]
we have
[tex]b=3.5\ m[/tex]
substitute
[tex]A=(3.5)^{2}=12.25\ m^{2}[/tex]
step 3
Find the difference of the areas
[tex]12.25\ m^{2}-9\ m^{2}=3.25\ m^{2}[/tex]