Respuesta :
Answer:
- 13,200 years
Explanation:
These steps explain how you estimate the age of the parchment:
1) Carbon - 14 half-life: τ = 5730 years
2) Number of half-lives elapsed: n
3) Age of the parchment = τ×n = 5730×n years = 5730n
4) Exponential decay:
The ratio of the final amount of the radioactive isotope C-14 to the initial amount of the same is one half (1/2) raised to the number of half-lives elapsed (n):
- A / Ao = (1/2)ⁿ
5) The parchment fragment had about 74% as much C-14 radioactivity as does plant material on Earth today:
- ⇒ A / Ao = 74% = 0.74
- ⇒ A / Ao = 0.74 = (1/2)ⁿ
- ⇒ ln (0.74) = n ln (1/2) [apply natural logarithm to both sides]
- ⇒ n = ln (1/2) / ln (0.74)
- ⇒ n ≈ - 0.693 / ( - 0.301) = 2.30
Hence, 2.30 half-lives have elapsed and the age of the parchment is:
- τ×n = 5730n = 5730 (2.30) = 13,179 years
- Round to the nearest hundred years: 13,200 years