Answer:
The lateral area of the pyramid is [tex]120\ cm^{2}[/tex]
Step-by-step explanation:
we know that
The lateral area of the pyramid is equal to the area of its three triangular lateral faces
so
[tex]LA=3[\frac{1}{2}(b)(k)][/tex]
where
[tex]b=10\ cm[/tex]
[tex]k=8\ cm[/tex] ------> the slant height
substitute the values
[tex]LA=3[\frac{1}{2}(10)(8)]=120\ cm^{2}[/tex]
