Answer:
12
Step-by-step explanation:
h'(x) = [f(x)*g(x)] '=f'(x )g(x) + f(x)g'(x)
h'(1) = [f(1)*g(1)] '=f '(1)g(1) + f(1)g'(1)
From the table f '(1)= -3, g(1)=2, f(1)= 3, g'(1) =6
h'(1) = f '(1)g(1) + f(1)g'(1) = -3*2 + 3*6= - 6+ 18 = 12
