Answer:
37.15 h.
Explanation:
where, k is the rate constant of the reaction (k = 2.4 x 10⁻² h⁻¹).
t is the time of the reaction (t = ??? day).
a is the initial concentration of nuclides (a = 100 %).
(a-x) is the remaining concentration of nuclides (a - x = 100% - 59% = 41.0 %).
∴ kt = lna/(a-x)
(2.4 x 10⁻² h⁻¹)(t) = ln(100.0%)/(41.0%).
(2.4 x 10⁻² h⁻¹)(t) = 0.8916.
∴ t = (0.8916)/(2.4 x 10⁻² h⁻¹) = 37.15 h.
