Answer: [tex]\bold{d.\ \sqrt[3]{-3}\cdot \sqrt[3]{-5} }[/tex]
Step-by-step explanation:
[tex]a)\ \sqrt[3]{-5}\cdot \sqrt[3]{3} =\sqrt[3]{-15}\neq \sqrt[3]{15} \\\\b)\ \sqrt[3]{-15}\cdot \sqrt[3]{1} =\sqrt[3]{-15}\neq \sqrt[3]{15}\\\\c)\ \sqrt[3]{5}\cdot \sqrt[3]{3} =\sqrt[3]{-15}\neq \sqrt[3]{15}\\\\\large{d)\ \sqrt[3]{-3}\cdot \sqrt[3]{-5} =\sqrt[3]{15}= \sqrt[3]{15} }[/tex]
