Answer:
120 kg m/s
Explanation:
The magnitude of the momentum of an object is given by
[tex]p=mv[/tex]
where
m is the mass of the object
v is its speed
For the block in this problem,
m = 10.0 kg (mass of the block)
v = 12.0 m/s (speed of the block)
Therefore the magnitude of the block's momentum is
[tex]p=(10.0 kg)(12.0 m/s)=120 kg m/s[/tex]
