Answer: [tex]\bold{2\sqrt[3]{15} }[/tex]
Step-by-step explanation:
[tex]\sqrt[3]{10} \cdot \sqrt[3]{12} =\sqrt[3]{2\cdot 5\cdot 2\cdot 2\cdot 3} =2\sqrt[3]{3\cdot 5} =\boxed{2\sqrt[3]{15}}[/tex]
