Answer:
[tex]m<JKL=38\°[/tex]
Step-by-step explanation:
we know that
The measurement of the external angle is the semi-difference of the arcs which comprises
In this problem
[tex]m<JKL=\frac{1}{2}(arc\ ML-arc\ MN)[/tex]
substitute the values
[tex]m<JKL=\frac{1}{2}(138\°-62\°)[/tex]
[tex]m<JKL=\frac{1}{2}(76\°)[/tex]
[tex]m<JKL=38\°[/tex]
