Two planes left simultaneously from the same airport and headed in the same direction towards another airport 1800 km away. The speed of one of the planes was 100 km/hour slower than the speed of the other plane, and so it arrived at its destination 36 minutes after the faster plane. Find the speeds of both planes.

Respuesta :

Answer:

Faster plane --> 600km/hr

Slower Plane --> 500km/hr

Step-by-step explanation:

Use inequality: 1800/r = 1800/(r-100) + 3/5 and solve to get r = 600, so the plane which is r -100 is 500 km/hr.