Which situation could NOT represent a proportional relationship? A) The cost of purchasing candy bars at a price of $1.25 per candy bar. B) The number of cookies produced in a factory at a rate of 1,000 cookies per hour. C) The cost of transporting an automobile for a charge of $1.00 per mile with a pick-up fee of $100. D) The cost of a field trip to a museum for a group of high school students at a cost of $10.00 per student.

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Answer:

Option C. The cost of transporting an automobile for a charge of $1.00 per mile with a pick-up fee of $100

Step-by-step explanation:

we know that          

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form [tex]y/x=k[/tex] or [tex]y=kx[/tex]

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

verify each case

case A) The cost of purchasing candy bars at a price of $1.25 per candy bar.      

Let

y------> the cost

x----> the number of candy bars

The linear equation that represent the situation is

y=1.25x -------> represent a proportional relationship

case B) The number of cookies produced in a factory at a rate of 1,000 cookies per hour

Let

y------> the number of cookies

x----> the number of hours

The linear equation that represent the situation is

y=1,000x -------> represent a proportional relationship

case C) The cost of transporting an automobile for a charge of $1.00 per mile with a pick-up fee of $100

Let

y------> the cost

x----> the number of miles

The linear equation that represent the situation is

y=x+100 -------> not represent a proportional relationship

case D) The cost of a field trip to a museum for a group of high school students at a cost of $10.00 per student

Let

y------> the cost

x----> the number of students

The linear equation that represent the situation is

y=10x -------> represent a proportional relationship

Answer: The answer is B.