Respuesta :

abhaysilver1
Here is your answer

d) [tex]r2= -5-\sqrt{5}[/tex]

REASON:

Equation is-

[tex] 2{x}^{2}+8x+c=0 [/tex]

Here,

a= 2; b= 8 and c=c

Now,

[tex] r1+r2= -b/a [/tex]

[Relation used: sum of zeroes=
-coefficient of x/ coefficient of x^2]

So,

[tex] 1+\sqrt{5} + r2= -8/2 [/tex]

[tex] 1+\sqrt{5} + r2= -4 [/tex]

[tex] r2= -4-1-\sqrt{5} [/tex]

[tex] r2= -5-\sqrt{5} [/tex]

HOPE IT IS USEFUL

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