meep26wesley
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If the angular velocity of the pully is -8.4rad/s at a given time, and its anglar acceleration is -2.8rad/s2, what is the angular velocity of the pulley 1.5s later?

Respuesta :

Here we know that

[tex]\omega_i = - 8.4 rad/s[/tex]

[tex]\alpha = - 2.8 rad/s^2[/tex]

[tex]t = 1.5 s[/tex]

now from kinematics we have

[tex]\omega_f = \omega_i + \alpha t[/tex]

now from above all values we have

[tex]\omega_f = (-8.4 rad/s) + (-2.8 rad/s^2)(1.5)[/tex]

[tex]\omega_f = -8.4 + (-4.2)[/tex]

[tex]\omega_f = -12.6 rad/s[/tex]

so final angular speed is -12.6 rad/s

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