Answer:
Part A)
The number of marbles that Su has at the beginning is [tex]25[/tex]
The number of marbles that Bertha has at the beginning is [tex]5[/tex]
Part B)
The number of marbles that Su has at the end is [tex]15[/tex]
The number of marbles that Bertha has at the end is [tex]15[/tex]
Step-by-step explanation:
Let
x------> number of marbles that Su has at the beginning
y------> number of marbles that Bertha has at the beginning
we know that
[tex]x=5y[/tex] ----> equation A
[tex]x-10=y+10[/tex] ----> equation B
substitute equation A in equation B
[tex](5y)-10=y+10[/tex]
[tex]4y=20[/tex]
[tex]y=5[/tex]
Find the value of x
[tex]x=5(5)=25[/tex]
Part A) How many marbles did they EACH have at the begining?
The number of marbles that Su has at the beginning is [tex]25[/tex]
The number of marbles that Bertha has at the beginning is [tex]5[/tex]
Part B) How many did they EACH have at the end?
[tex]x-10=y+10[/tex]
so
[tex]25-10=5+10[/tex]
[tex]15=15[/tex]
therefore
The number of marbles that Su has at the end is [tex]15[/tex]
The number of marbles that Bertha has at the end is [tex]15[/tex]
