Answer:
Part a) The inequality that represent the situation is
[tex]x+(3x)+(6x) \leq 350\ in[/tex]
Part b) The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to [tex]35\ inches[/tex]
Step-by-step explanation:
Let
x------> the length of the first wire
3x---> the length of the second wire
2(3x)=6x -----> the length of the third wire
Part a) WRITE AN *INEQUALITY* THAT MODELS THE SITUATION
we know that
The inequality that represent the situation is
[tex]x+(3x)+(6x) \leq 350[/tex]
Part b) WHAT ARE THE POSSIBLE LENGTHS OF THE SHORTEST PIECE OF WIRE?
we know that
The shortest piece of wire is the first wire
so
Solve the inequality
[tex]x+(3x)+(6x) \leq 350[/tex]
[tex]10x \leq 350[/tex]
[tex]x \leq 35\ in[/tex]
The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to [tex]35\ inches[/tex]