Answer:
[tex]y=4x-1[/tex]
Step-by-step explanation:
The point-slope equation of the line is [tex]y-y_0=m(x-x_0),[/tex]
where [tex]m[/tex] is the slope and [tex](x_0,y_0)[/tex] are the coordinates of the point the line is passing through.
In your case,
[tex]m=4,\\ \\x_0=3,\\ \\y_0=11.[/tex]
Thus, the equation of the line is
[tex]y-11=4(x-3),\\ \\y=4x-12+11,\\ \\y=4x-1.[/tex]
