Here we know that current is defined as rate of flow of charge
so here we have
[tex]i = \frac{dQ}{dt}[/tex]
here we also know that
Q = Ne
now we have
[tex]i = \frac{Ne}{t}[/tex]
now in order to find time we have
[tex]t = \frac{Ne}{i}[/tex]
here we know that
[tex]N = 1.17 \times 10^{15}[/tex]
[tex]e = 1.602 \times 10^{-19}C[/tex]
[tex]i = 5.8 \times 10^{-5}A[/tex]
now we have
[tex]t = \frac{1.17\times 10^{15} (1.602 \times 10^{-19}}{5.8 \times 10^{-5}}[/tex]
[tex]t = 3.23 s[/tex]
It would take 3.23 s to the electrons strike the screen.
To solve this issue, it is necessary to use the current, which relates the total charge of the electrons and the time required for the movement, so that:
[tex]i = \frac{Q}{t} = \frac{e\times N}{t}[/tex]
So, with the values given by the question we have:
[tex]5.8\times 10^{-5} = \frac{1.17 \times 10^{15} \times 1.602\times10^{-19}}{t}[/tex]
[tex]t = 3.23s[/tex]
So, it would take 3.23 s to the electrons strike the screen.
Learn more about current in: brainly.com/question/2285102
