Answer:
[tex]5.9\cdot 10^4 N[/tex]
Explanation:
First of all, let's convert the area of the front side of the person into [tex]m^2[/tex]:
[tex]A=900 in^2=0.58 m^2[/tex]
And the atmospheric pressure is
[tex]p=1.01 \cdot 10^5 Pa[/tex]
The force pressing on this person from the front side is
[tex]F=pA[/tex]
and substituting the values of the pressure and the area, we find
[tex]F=(1.01 \cdot 10^5 Pa)(0.58 m^2)=58,580 N=5.9\cdot 10^4 N[/tex]
