Here we can say that there is no external torque on this system
So here we can say that angular momentum is conserved
so here we will have
[tex]I_1\omega_1 = I_2\omega_2[/tex]
now we have
[tex]I_1 = mr^2[/tex]
[tex]I_1 = (1kg)(0.05^2)[/tex]
[tex]I_1 = 25\times 10^{-4} kg m^2[/tex]
similarly let the final distance is "r"
so now we have
[tex]I_2 = mr^2[/tex]
[tex]I_2 = 1r^2[/tex]
now from above equation we have
[tex](25\times 10^{-4})37 = (r^2)(58)[/tex]
[tex]r = 0.04 m[/tex]
so final distance is 0.04 m between them
